What Is the Equation to Calculate the Speed of Light and Energy?

The speed of light in a vacuum is a fixed, universal constant: c = 3.00x10^8 m/s, to three significant digits. The relationship between the speed of an electromagnetic wave, its frequency and wavelength is given by: c = f ..... where f is frequency and is the wavelength The energy of an electromagnetic wave is given by: E = h f ... where h = Planck's constant, 6.63x10^-34 Js Since f = c / we can make the following substitution and get: E = hc /

1. How do light bulbs convert energy from eletrical energy to light energy?

Upon tuning on the light, an electrical voltage difference exists across a component of the light bulb called the filament. The filament is nothing more than a tiny jumble of tungsten wire, which is surrounded by Argon to prevent chemical reactions. This voltage difference causes a corresponding electrical current to flow through the filament. The product of the voltage difference and the current flow gives us the rate at which electrical energy is consumed by the bulb. When the electrical energy is consumed by the bulb, it heats the filament due to the resistive heating effect. When the filament reaches a steady state temperature, it is emitting this amount of energy as thermal radiation. Because the filament is hot enough (2600 Kelvin), the spectrum of the radiation includes some visible light, while mostly infrared. The glass lets through all the visible light and some high frequency IR, but absorbs much of the IR and converts to heat. For this reason, the light bulb glass gets hot when operated. Summary: electrical energy is converted to thermal energy via the resistive nature of the tungsten filament. This thermal energy is emitted as radiation by the filament in order to maintain a steady state temperature. Because the filament is hot enough, some of the spectrum of emitted radiation is visible, while the rest eventually manifests as heat, whether in the glass or upon striking our skin.

2. light energy question?

it does makes sense, the solar cells can be placed in an area of land and the power generated from it can be transferred to the houses.so, it depends on how many square miles of photocells u need to generate 250000kW power

3. Whats the diff between light energy and light frequency?

Light frequency is the specific vibrational number that also specifies the color. Shorter wave lengths have higher frequency so Blue and UV have higher frequency than Red and IR. The energy in the photons goes up with frequency.

4. What exactly is Light Energy?

Energy can not be created or destroyed, it just changes form in the form of light, or heat. A law of physics, this can be proven by lighting a fire cracker. Potential energy is ignited (excited) and is transformed into light, and heat energy, "BANG", and it's a flash of light, and heat energy.

5. What SI unit is used to express light energy, and how is this unit converted into joules?

The SI unit of light energy is the joule.One of the major points of using the SI is that it supports a coherent system of measurement, avoiding weird conversion factors between units measuring the same quantity.There does appear to be some confusion about what the questioner intends. Regarding Mike Schneids' answer to What SI unit is used to express light energy, and how is this unit converted into joules?, energy in electron volts is commonly used to describe the energy of an individual photon, but is rarely used more generally to describe "light energy". Furthermore, in the jargon of International System of Units - Wikipedia, the electron volt is a "non-SI unit whose value in SI units must be obtained experimentally". In other words eV is not an SI unit.However, while radiant energy is measured (like any other form of energy) in joules, SI also includes the concept of luminous energy.Luminous energy is the perceived quantity of light, related to how bright it appears to a typical human observer. The unit is lumen-second (lm cdot s). The actual energy in joules is weighted by the human photopic response or luminosity function.Luminosity function - WikipediaPhotopic (black) and scotopic (green) luminosity functions. The photopic includes the CIE 1931 standard (solid), the Judd-Vos 1978 modified data (dashed), and the Sharpe, Stockman, Jagla & Jgle 2005 data (dotted). The horizontal axis is wavelength in nm. The luminosity function V(lambda) has peak value equal to unity at wavelength lambda 555 nm.Luminous energy in lumen-seconds depends on the spectral distribution q_e,lambda of radiant energy: Q_V = K_m int V(lambda) q_e,lambda dlambda The conversion factor between lumens and watts, or between lumen-seconds and joules is K_m = 683.002 , lm , W^-1Conversion is trivial for monochromatic light with frequency 540 THz (550. 016 nm) for which the conversion factor is defined to be 683 lm/W exactly. More generally, the spectral distribution must be accounted for, using the integral equation for Q_V above.What SI unit is used to express light energy, and how is this unit converted into joules?.

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Low-Energy Intense Pulsed Light for Hair Removal at HomeLow-energy intense pulsed light for hair removal at home was evaluated in this clinical trial. Twenty-two female patients were enrolled into an institutional review board-approved clinical trial. Patients received six biweekly treatments with the device, and clinical results with hair counts and pictures were performed at four weeks and three months following the last treatment. Source: ncbi.nlm.nih.gov/pmc/articles/PMC2921762/Guidelines on the Safety of Light-based Home-use Hair Removal Devices From the European Society for Laser DermatologyIn the past 5 years since their US introduction, there has been a rapid proliferation of light-based hair removal devices intended for home-use. In the last 2 years in Europe, sales already run into many tens of thousands of units with well-known multi-national companies entering the market. These guidelines provide a definition of light-based home-use technology, to inform healthcare professionals about home-use light-based technology and encourage manufacturers wishing to sell in Europe to adopt best practice. Source: researchgate.net/publication/51974851_Guidelines_on_the_safety_of_light-based_home-use_hair_removal_devices_from_the_European_Society_for_Laser_DermatologyThe Pros and Cons of At-Home Laser Hair RemovalLaser hair removal devices work by killing the hair follicle. But hair grows in cycles, and the lasers only damage follicles during an active cycle of hair growth. So it takes multiple treatments, about a month apart, to completely stop hair from regrowing.Source: clevelandclinic.org/the-pros-and-cons-of-at-home-laser-hair-removal/Thinking of Laser Hair Removal? Heres What You Need to KnowLasers emit a wavelength of light with a specific single colour. When targeted to the skin, the energy from the light is transferred to the skin and hair pigment melanin. This heats up and damages the surrounding tissue.Source: com/thinking-of-laser-hair-removal-heres-what-you-need-to-know-113561Hair Removal Statistics Share of Men and WomenThis statistic shows the share of men and women aged 16 years and older, who removed their body hair in Great Britain in 2016. Of female respondents, 89 percent reported removing their body hair.Source: ·RELATED QUESTIONHow to determine the amount of light energy (photons) being released from an incandescent light bulb?The title of this question refers to the emission of light from an incandescent light bulb, and then the body of the question asks for Planck-scale details of the physics happening there. Well, that would be a lot of work to answer. Suppose it's a tungsten filament. Then there's a molecular lattice of tungsten atoms, i.e. a lattice of nuclei surrounded by electron shells embedded in a "Fermi liquid" of conducting electrons. The nuclei are spinning balls of protons and neutrons exchanging pions; the protons, neutrons and pions are all made of quarks and gluons. The electrons in the shells are electromagnetically attracted to the protons in the nuclei. The conducting electrons are also attracted, but their wavefunctions are spread out in space, throughout the tungsten wire. As John Rennie's comment points out, the emission of photons from an incandescent light bulb comes from these spread-out conducting electrons, not from the localized electrons in the electron shells. Emission of photons from electrons associated with a single atom, is more characteristic of a gas, where the atoms are floating free. But there is a sub-question about how the quarks in the nucleus respond to the electron emitting a photon, and that's easier to answer in the case of a free atom. Basically, there is no effect, but I should be able to explain why. The effect on an atom, when one of its electrons emits a photon, might be vaguely like what would happen, if you had a balloon with some marbles inside it, and then you tapped on the balloon. The balloon would move away, but it would wobble and the marbles would rattle against each other. Here the balloon is the wavefunction of the electron which emits the photon, the tap on the balloon is the impulse that the electron experiences in the opposite direction to the photon, and the marbles are the wavefunctions of the quarks, or even of the protons and neutrons. I think the main thing to understand is that when the photon is emitted, conservation of momentum means that the electron, and then the whole atom, will start moving in the opposite direction, but very very slowly. If you think of the balloon again, and suppose it was floating there but with a fly resting on it, and then the fly took off. The balloon would start moving away in the opposite direction to the fly, but very very slowly. The whole atom would move back from the emission of the photon, but only slowly, and the effect in the nucleus is indirect, like the rattling of the marbles in the balloon. So the recoil on the atom is almost zero, and it will be completely drowned out if there are other forces acting on the atom, e.g. if the atom is bonded to other atoms and the whole structure is vibrating with heat. Returning to the general topic of the subatomic physics of incandescence, or the subatomic physics of anything, the main challenge for any questioner is going to be, understanding what wavefunctions are. It's a wave, that can be spread out in space, or concentrated around one point, which gives the probability for the particle being there. If the "wave" is high in some region, then the probability is high that the particle is in there; but there is also a probability that it is somewhere out in the much larger region where the wave is low. The way these waves behave has a lot in common with the older ideas of particles experiencing forces, e.g. the old idea of an electron orbiting the nucleus like a planet orbiting a star. The waves in the electron's wavefunction do travel from place to place; but they can also be in an equilibrium configuration, just pulsing on the spot; the energy levels for electrons in an atom are like this. The big question is, what is actually there? Are the waves real; or is the reality a particle moving around, and the math of waves is just because we don't know where it is; or maybe the reality is some third option? I'm sorry to say that you won't get very sensible answers to this question from physicists. You will get different answers from different physicists, including excuses for not having a proper answer. This picture of probability waves for particles is about as far as physics has progressed. It provides enough logic and visualization, that many many things can be understood, and predicted with amazing detail. For example, it's a framework capable of describing and explaining incandescent light sources, in terms of what the atoms are doing. But if you want something deeper and more logical than probability waves, you'll just have to wait for the next big leap in physics
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